0=48m^2+150m-168

Solution for 0=48m^2+150m-168 equation:

0=48m^2+150m-168

We move all terms to the left:

0-(48m^2+150m-168)=0

We add all the numbers together, and all the variables

-(48m^2+150m-168)=0

We get rid of parentheses

-48m^2-150m+168=0

a = -48; b = -150; c = +168;
Δ = b2-4ac
Δ = -1502-4·(-48)·168
Δ = 54756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{54756}=234$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-234}{2*-48}=\frac{-84}{-96}
=7/8
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+234}{2*-48}=\frac{384}{-96}
=-4
$